12/2=4n/(n-2)

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Solution for 12/2=4n/(n-2) equation: 



12/2=4n/(n-2)

We move all terms to the left:

12/2-(4n/(n-2))=0



Domain of the equation: (n-2))!=0

n∈R



We add all the numbers together, and all the variables

-(4n/(n-2))+6=0

We multiply all the terms by the denominator


-(4n+6*(n-2))=0



We calculate terms in parentheses: -(4n+6*(n-2)), so:

4n+6*(n-2)

We multiply parentheses

4n+6n-12

We add all the numbers together, and all the variables

10n-12

Back to the equation:

-(10n-12)



We get rid of parentheses

-10n+12=0

We move all terms containing n to the left, all other terms to the right

-10n=-12

n=-12/-10

n=1+1/5

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