12/2b=5

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Solution for 12/2b=5 equation: 



12/2b=5

We move all terms to the left:

12/2b-(5)=0



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



We multiply all the terms by the denominator


-5*2b+12=0

Wy multiply elements

-10b+12=0

We move all terms containing b to the left, all other terms to the right

-10b=-12

b=-12/-10

b=1+1/5

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