12/2k=3

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Solution for 12/2k=3 equation: 



12/2k=3

We move all terms to the left:

12/2k-(3)=0



Domain of the equation: 2k!=0

k!=0/2

k!=0

k∈R



We multiply all the terms by the denominator


-3*2k+12=0

Wy multiply elements

-6k+12=0

We move all terms containing k to the left, all other terms to the right

-6k=-12

k=-12/-6

k=+2

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