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12/2m-1=12/m+4
We move all terms to the left:
12/2m-1-(12/m+4)=0
Domain of the equation: 2m!=0
m!=0/2
m!=0
m∈R
Domain of the equation: m+4)!=0We get rid of parentheses
m∈R
12/2m-12/m-4-1=0
We calculate fractions
12m/2m^2+(-24m)/2m^2-4-1=0
We add all the numbers together, and all the variables
12m/2m^2+(-24m)/2m^2-5=0
We multiply all the terms by the denominator
12m+(-24m)-5*2m^2=0
Wy multiply elements
-10m^2+12m+(-24m)=0
We get rid of parentheses
-10m^2+12m-24m=0
We add all the numbers together, and all the variables
-10m^2-12m=0
a = -10; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·(-10)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*-10}=\frac{0}{-20} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*-10}=\frac{24}{-20} =-1+1/5 $
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