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12/2x+12/2=12/1x
We move all terms to the left:
12/2x+12/2-(12/1x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 1x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
12/2x-(+12/1x)+12/2=0
We add all the numbers together, and all the variables
12/2x-(+12/1x)+6=0
We get rid of parentheses
12/2x-12/1x+6=0
We calculate fractions
12x/2x^2+(-24x)/2x^2+6=0
We multiply all the terms by the denominator
12x+(-24x)+6*2x^2=0
Wy multiply elements
12x^2+12x+(-24x)=0
We get rid of parentheses
12x^2+12x-24x=0
We add all the numbers together, and all the variables
12x^2-12x=0
a = 12; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·12·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*12}=\frac{24}{24} =1 $
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