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12/2x+4=2/x-2
We move all terms to the left:
12/2x+4-(2/x-2)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x-2)!=0We get rid of parentheses
x∈R
12/2x-2/x+2+4=0
We calculate fractions
12x/2x^2+(-4x)/2x^2+2+4=0
We add all the numbers together, and all the variables
12x/2x^2+(-4x)/2x^2+6=0
We multiply all the terms by the denominator
12x+(-4x)+6*2x^2=0
Wy multiply elements
12x^2+12x+(-4x)=0
We get rid of parentheses
12x^2+12x-4x=0
We add all the numbers together, and all the variables
12x^2+8x=0
a = 12; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·12·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*12}=\frac{-16}{24} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*12}=\frac{0}{24} =0 $
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