12/3+3n=(4/5)n+18

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Solution for 12/3+3n=(4/5)n+18 equation: 



12/3+3n=(4/5)n+18

We move all terms to the left:

12/3+3n-((4/5)n+18)=0



Domain of the equation: 5)n+18)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

3n-((+4/5)n+18)+12/3=0

We add all the numbers together, and all the variables

3n-((+4/5)n+18)+4=0

We multiply all the terms by the denominator


3n*5)n+18)-((+4*5)n+18)+4=0

We add all the numbers together, and all the variables

3n*5)n+18)-(20n+18)+4=0

Wy multiply elements

15n^2=0

a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{30}=0$

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