12/3=44x2=8

Solution for 12/3=44x2=8 equation:

12/3=44x^2=8

We move all terms to the left:

12/3-(44x^2)=0

We add all the numbers together, and all the variables

-44x^2+4=0

a = -44; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-44)·4
Δ = 704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{704}=\sqrt{64*11}=\sqrt{64}*\sqrt{11}=8\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{11}}{2*-44}=\frac{0-8\sqrt{11}}{-88}
=-\frac{8\sqrt{11}}{-88}
=-\frac{\sqrt{11}}{-11}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{11}}{2*-44}=\frac{0+8\sqrt{11}}{-88}
=\frac{8\sqrt{11}}{-88}
=\frac{\sqrt{11}}{-11}
$