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12/3=x-5/x+4
We move all terms to the left:
12/3-(x-5/x+4)=0
Domain of the equation: x+4)!=0We add all the numbers together, and all the variables
x∈R
-(x-5/x+4)+4=0
We get rid of parentheses
-x+5/x-4+4=0
We multiply all the terms by the denominator
-x*x-4*x+4*x+5=0
We add all the numbers together, and all the variables
-x*x+5=0
Wy multiply elements
-1x^2+5=0
a = -1; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-1)·5
Δ = 20
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20}=\sqrt{4*5}=\sqrt{4}*\sqrt{5}=2\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{5}}{2*-1}=\frac{0-2\sqrt{5}}{-2} =-\frac{2\sqrt{5}}{-2} =-\frac{\sqrt{5}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{5}}{2*-1}=\frac{0+2\sqrt{5}}{-2} =\frac{2\sqrt{5}}{-2} =\frac{\sqrt{5}}{-1} $
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