12/3x+12/2x=44

Solution for 12/3x+12/2x=44 equation:

12/3x+12/2x=44

We move all terms to the left:

12/3x+12/2x-(44)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We calculate fractions


24x/6x^2+36x/6x^2-44=0

We multiply all the terms by the denominator


24x+36x-44*6x^2=0

We add all the numbers together, and all the variables

60x-44*6x^2=0

Wy multiply elements

-264x^2+60x=0

a = -264; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·(-264)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*-264}=\frac{-120}{-528}
=5/22
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*-264}=\frac{0}{-528}
=0
$