If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12/3x+1=3/x
We move all terms to the left:
12/3x+1-(3/x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
12/3x-(+3/x)+1=0
We get rid of parentheses
12/3x-3/x+1=0
We calculate fractions
12x/3x^2+(-9x)/3x^2+1=0
We multiply all the terms by the denominator
12x+(-9x)+1*3x^2=0
Wy multiply elements
3x^2+12x+(-9x)=0
We get rid of parentheses
3x^2+12x-9x=0
We add all the numbers together, and all the variables
3x^2+3x=0
a = 3; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·3·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*3}=\frac{-6}{6} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*3}=\frac{0}{6} =0 $
| 4(k-62)=96 | | 7/2×-30=2/x | | 2x4^4x=32 | | 57(x−2)−34(x+3)=−4 | | 3b+–6=3 | | 4t+6=-14 | | 5(x-2)+50=400 | | 6+2m+8=-2 | | -14=-7+m/2 | | 3(b+4=2b+40 | | -6p+10=-62 | | -137=7+8n | | 6(s+2)−5s=16+s−4 | | 4m+5+2m=3+4 | | 4m+5-2m+3=4 | | 34-g=-32 | | (2m3)(m)(m)= | | -11=m/10 | | 2.7x-2.5=- | | 15x-11=32 | | -5+3c=13 | | 15x-6=32 | | -4=-2f=-10 | | -92=7x+2(2x+9) | | 8x-13=32 | | 7x+12=5x-20 | | 77-x=167 | | 10^-5=x^2/(0.1-x) | | 4x-2(4x-17)=14 | | 7x-12=6x-12 | | x/5=−5 | | 9x-12=4x-22 |