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12/4x-3=3/x
We move all terms to the left:
12/4x-3-(3/x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
12/4x-(+3/x)-3=0
We get rid of parentheses
12/4x-3/x-3=0
We calculate fractions
12x/4x^2+(-12x)/4x^2-3=0
We multiply all the terms by the denominator
12x+(-12x)-3*4x^2=0
Wy multiply elements
-12x^2+12x+(-12x)=0
We get rid of parentheses
-12x^2+12x-12x=0
We add all the numbers together, and all the variables
-12x^2=0
a = -12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-12)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-24}=0$
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