12/5t=40

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Solution for 12/5t=40 equation: 



12/5t=40

We move all terms to the left:

12/5t-(40)=0



Domain of the equation: 5t!=0

t!=0/5

t!=0

t∈R



We multiply all the terms by the denominator


-40*5t+12=0

Wy multiply elements

-200t+12=0

We move all terms containing t to the left, all other terms to the right

-200t=-12

t=-12/-200

t=3/50

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