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12/5x=2
We move all terms to the left:
12/5x-(2)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
-2*5x+12=0
Wy multiply elements
-10x+12=0
We move all terms containing x to the left, all other terms to the right
-10x=-12
x=-12/-10
x=1+1/5
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