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12/5y-8=3/5y+10
We move all terms to the left:
12/5y-8-(3/5y+10)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 5y+10)!=0We get rid of parentheses
y∈R
12/5y-3/5y-10-8=0
We multiply all the terms by the denominator
-10*5y-8*5y+12-3=0
We add all the numbers together, and all the variables
-10*5y-8*5y+9=0
Wy multiply elements
-50y-40y+9=0
We add all the numbers together, and all the variables
-90y+9=0
We move all terms containing y to the left, all other terms to the right
-90y=-9
y=-9/-90
y=1/10
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