If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12/7=-7/2x
We move all terms to the left:
12/7-(-7/2x)=0
Domain of the equation: 2x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
7/2x+12/7=0
We calculate fractions
There is no solution for this equation
| 5x2-√5(3√5x+2√5)=0 | | 9/x=-10/3 | | k/33=36/44 | | 5x2−5√(35√x+25√)=0 | | k33=3644 | | 7k-9=16 | | 9/x=10/3 | | 3g=915 | | 5=x+23 | | 1/2x+5*8=x | | 1.6=j/1.5 | | x+1=-1+(-5) | | p(5.5)=p(8) | | 3/7+l=17/7 | | -18x=55+2x+415 | | 6=c+2 | | -18x+55=2x=415 | | 4-x/2=7 | | 4=3(2x+1)-1 | | 2x+3=x+29 | | 4x+(-3)=5x-3 | | 22.50x+27.50=250 | | 6+6X6-6=x | | -2x+8(x-24)=36 | | (65+25)x=400+25x | | 7(4k-15)=-6(4+2k) | | 162=-16t^2+100t+6 | | 4x+12=80-x | | 1224x=5000 | | 1/7(x+8)+3/2x=10 | | 9x-3x-x-2=4x | | 3(m-2)=m-2 |