12/8x+12/8=-6/9x+8

Solution for 12/8x+12/8=-6/9x+8 equation:

12/8x+12/8=-6/9x+8

We move all terms to the left:

12/8x+12/8-(-6/9x+8)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 9x+8)!=0

x∈R


We get rid of parentheses

12/8x+6/9x-8+12/8=0

We calculate fractions


108x/4608x^2+3072x/4608x^2+108x/4608x^2-8=0

We multiply all the terms by the denominator


108x+3072x+108x-8*4608x^2=0

We add all the numbers together, and all the variables

3288x-8*4608x^2=0

Wy multiply elements

-36864x^2+3288x=0

a = -36864; b = 3288; c = 0;
Δ = b2-4ac
Δ = 32882-4·(-36864)·0
Δ = 10810944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10810944}=3288$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3288)-3288}{2*-36864}=\frac{-6576}{-73728}
=137/1536
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3288)+3288}{2*-36864}=\frac{0}{-73728}
=0
$