12/t+t-8=0

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Solution for 12/t+t-8=0 equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

t+12/t-8 = 0

1*t^1+12*t^-1-8*t^0 = 0

(1*t^2-8*t^1+12*t^0)/(t^1) = 0 // * t^2

t^1*(1*t^2-8*t^1+12*t^0) = 0

t^1

t^2-8*t+12 = 0

t^2-8*t+12 = 0

DELTA = (-8)^2-(1*4*12)

DELTA = 16

DELTA > 0

t = (16^(1/2)+8)/(1*2) or t = (8-16^(1/2))/(1*2)

t = 6 or t = 2

t in { 2, 6} 

t in { 2, 6 }

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