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12/x+4=9/2x
We move all terms to the left:
12/x+4-(9/2x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
12/x-(+9/2x)+4=0
We get rid of parentheses
12/x-9/2x+4=0
We calculate fractions
24x/2x^2+(-9x)/2x^2+4=0
We multiply all the terms by the denominator
24x+(-9x)+4*2x^2=0
Wy multiply elements
8x^2+24x+(-9x)=0
We get rid of parentheses
8x^2+24x-9x=0
We add all the numbers together, and all the variables
8x^2+15x=0
a = 8; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·8·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*8}=\frac{-30}{16} =-1+7/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*8}=\frac{0}{16} =0 $
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