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12/x=1+12/(x+1)
We move all terms to the left:
12/x-(1+12/(x+1))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+1))!=0We calculate fractions
x∈R
12x/2x^2+(-(1+12*x)/2x^2=0
We add all the numbers together, and all the variables
12x/2x^2+(-(12x+1)/2x^2=0
We multiply all the terms by the denominator
12x+(-(12x+1)=0
We calculate terms in parentheses: +(-(12x+1), so:
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| 2(x+2)=4(x-12) | | 3x+2+2x-1=33 | | (12/x)-(12/(x+1))=1 | | -8-x=3x+6 | | (5-2i)+(3+7i)=0 | | 2x-9+6=15 | | 4x+1=11x-3 | | |r/4|=3 | | 60°8x-4=180 | | n-12.1=23 | | 4y^2+12y=7 | | b+40=12b-48 | | 4(p+1)=64 | | f+52.8=75 | | 3/y=81 | | 4(k-6=20 | | 10x+1=156 | | 4t-34=2t+2 | | 3.5x=−21 | | 3/5p-4/5=2/5 | | X^2+24x-88=0 | | 9z+9=108 | | 3x+5=7x-5=90 | | 16s-24=s+36 | | 2x^{2}-8=120 | | t+36=5t | | 5n+7=7(n-1)-n | | 2x+40+4x-10=55+5x | | (19+x)/4=31 | | X+260=2x | | 2(x+3)=3(x-1)+5x | | 3y+3=15+3 |