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12/x=2x+7/3x+8
We move all terms to the left:
12/x-(2x+7/3x+8)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x+8)!=0We get rid of parentheses
x∈R
12/x-2x-7/3x-8=0
We calculate fractions
-2x+36x/3x^2+(-7x)/3x^2-8=0
We multiply all the terms by the denominator
-2x*3x^2+36x+(-7x)-8*3x^2=0
We add all the numbers together, and all the variables
36x-2x*3x^2+(-7x)-8*3x^2=0
Wy multiply elements
-6x^3-24x^2+36x+(-7x)=0
We get rid of parentheses
-6x^3-24x^2+36x-7x=0
We do not support expression: x^3
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