120+4y=2(5y+4)+2(2y+6)

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Solution for 120+4y=2(5y+4)+2(2y+6) equation: 



120+4y=2(5y+4)+2(2y+6)

We move all terms to the left:

120+4y-(2(5y+4)+2(2y+6))=0



We calculate terms in parentheses: -(2(5y+4)+2(2y+6)), so:

2(5y+4)+2(2y+6)

We multiply parentheses

10y+4y+8+12

We add all the numbers together, and all the variables

14y+20

Back to the equation:

-(14y+20)



We get rid of parentheses

4y-14y-20+120=0

We add all the numbers together, and all the variables

-10y+100=0

We move all terms containing y to the left, all other terms to the right

-10y=-100

y=-100/-10

y=+10

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