120+72+(1/4x)=x

Solution for 120+72+(1/4x)=x equation:

120+72+(1/4x)=x

We move all terms to the left:

120+72+(1/4x)-(x)=0


Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/4x)-x+120+72=0

We add all the numbers together, and all the variables

-1x+(+1/4x)+192=0

We get rid of parentheses

-1x+1/4x+192=0

We multiply all the terms by the denominator


-1x*4x+192*4x+1=0

Wy multiply elements

-4x^2+768x+1=0

a = -4; b = 768; c = +1;
Δ = b2-4ac
Δ = 7682-4·(-4)·1
Δ = 589840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{589840}=\sqrt{16*36865}=\sqrt{16}*\sqrt{36865}=4\sqrt{36865}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(768)-4\sqrt{36865}}{2*-4}=\frac{-768-4\sqrt{36865}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(768)+4\sqrt{36865}}{2*-4}=\frac{-768+4\sqrt{36865}}{-8}
$