120/x+300/2x=9

Solution for 120/x+300/2x=9 equation:

120/x+300/2x=9

We move all terms to the left:

120/x+300/2x-(9)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We calculate fractions


240x/2x^2+300x/2x^2-9=0

We multiply all the terms by the denominator


240x+300x-9*2x^2=0

We add all the numbers together, and all the variables

540x-9*2x^2=0

Wy multiply elements

-18x^2+540x=0

a = -18; b = 540; c = 0;
Δ = b2-4ac
Δ = 5402-4·(-18)·0
Δ = 291600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{291600}=540$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(540)-540}{2*-18}=\frac{-1080}{-36}
=+30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(540)+540}{2*-18}=\frac{0}{-36}
=0
$