1200-200(p+1)=-400+200(p+1)

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Solution for 1200-200(p+1)=-400+200(p+1) equation: 



1200-200(p+1)=-400+200(p+1)

We move all terms to the left:

1200-200(p+1)-(-400+200(p+1))=0

We multiply parentheses

-200p-(-400+200(p+1))-200+1200=0



We calculate terms in parentheses: -(-400+200(p+1)), so:

-400+200(p+1)

determiningTheFunctionDomain
200(p+1)-400

We multiply parentheses

200p+200-400

We add all the numbers together, and all the variables

200p-200

Back to the equation:

-(200p-200)



We add all the numbers together, and all the variables

-200p-(200p-200)+1000=0

We get rid of parentheses

-200p-200p+200+1000=0

We add all the numbers together, and all the variables

-400p+1200=0

We move all terms containing p to the left, all other terms to the right

-400p=-1200

p=-1200/-400

p=+3

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