1200=(x+150)+x

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Solution for 1200=(x+150)+x equation: 



1200=(x+150)+x

We move all terms to the left:

1200-((x+150)+x)=0



We calculate terms in parentheses: -((x+150)+x), so:

(x+150)+x

We add all the numbers together, and all the variables

x+(x+150)

We get rid of parentheses

x+x+150

We add all the numbers together, and all the variables

2x+150

Back to the equation:

-(2x+150)



We get rid of parentheses

-2x-150+1200=0

We add all the numbers together, and all the variables

-2x+1050=0

We move all terms containing x to the left, all other terms to the right

-2x=-1050

x=-1050/-2

x=+525

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