120=(2x+3)+2(2x-2)

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Solution for 120=(2x+3)+2(2x-2) equation: 



120=(2x+3)+2(2x-2)

We move all terms to the left:

120-((2x+3)+2(2x-2))=0



We calculate terms in parentheses: -((2x+3)+2(2x-2)), so:

(2x+3)+2(2x-2)

We multiply parentheses

(2x+3)+4x-4

We get rid of parentheses

2x+4x+3-4

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We get rid of parentheses

-6x+1+120=0

We add all the numbers together, and all the variables

-6x+121=0

We move all terms containing x to the left, all other terms to the right

-6x=-121

x=-121/-6

x=20+1/6

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