120=(2x-1)(x)

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Solution for 120=(2x-1)(x) equation:



120=(2x-1)(x)
We move all terms to the left:
120-((2x-1)(x))=0
We calculate terms in parentheses: -((2x-1)x), so:
(2x-1)x
We multiply parentheses
2x^2-1x
Back to the equation:
-(2x^2-1x)
We get rid of parentheses
-2x^2+1x+120=0
We add all the numbers together, and all the variables
-2x^2+x+120=0
a = -2; b = 1; c = +120;
Δ = b2-4ac
Δ = 12-4·(-2)·120
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-31}{2*-2}=\frac{-32}{-4} =+8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+31}{2*-2}=\frac{30}{-4} =-7+1/2 $

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