120=(n+1)+(n-1)+5

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Solution for 120=(n+1)+(n-1)+5 equation: 



120=(n+1)+(n-1)+5

We move all terms to the left:

120-((n+1)+(n-1)+5)=0



We calculate terms in parentheses: -((n+1)+(n-1)+5), so:

(n+1)+(n-1)+5

We get rid of parentheses

n+n+1-1+5

We add all the numbers together, and all the variables

2n+5

Back to the equation:

-(2n+5)



We get rid of parentheses

-2n-5+120=0

We add all the numbers together, and all the variables

-2n+115=0

We move all terms containing n to the left, all other terms to the right

-2n=-115

n=-115/-2

n=57+1/2

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