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120=3x*x
We move all terms to the left:
120-(3x*x)=0
We add all the numbers together, and all the variables
-(+3x*x)+120=0
We get rid of parentheses
-3x*x+120=0
Wy multiply elements
-3x^2+120=0
a = -3; b = 0; c = +120;
Δ = b2-4ac
Δ = 02-4·(-3)·120
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{10}}{2*-3}=\frac{0-12\sqrt{10}}{-6} =-\frac{12\sqrt{10}}{-6} =-\frac{2\sqrt{10}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{10}}{2*-3}=\frac{0+12\sqrt{10}}{-6} =\frac{12\sqrt{10}}{-6} =\frac{2\sqrt{10}}{-1} $
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