1210=s2

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Solution for 1210=s2 equation:



1210=s2
We move all terms to the left:
1210-(s2)=0
We add all the numbers together, and all the variables
-1s^2+1210=0
a = -1; b = 0; c = +1210;
Δ = b2-4ac
Δ = 02-4·(-1)·1210
Δ = 4840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{4840}=\sqrt{484*10}=\sqrt{484}*\sqrt{10}=22\sqrt{10}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{10}}{2*-1}=\frac{0-22\sqrt{10}}{-2} =-\frac{22\sqrt{10}}{-2} =-\frac{11\sqrt{10}}{-1} $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{10}}{2*-1}=\frac{0+22\sqrt{10}}{-2} =\frac{22\sqrt{10}}{-2} =\frac{11\sqrt{10}}{-1} $

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