1210=s2

Solution for 1210=s2 equation:

1210=s2

We move all terms to the left:

1210-(s2)=0

We add all the numbers together, and all the variables

-1s^2+1210=0

a = -1; b = 0; c = +1210;
Δ = b2-4ac
Δ = 02-4·(-1)·1210
Δ = 4840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4840}=\sqrt{484*10}=\sqrt{484}*\sqrt{10}=22\sqrt{10}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{10}}{2*-1}=\frac{0-22\sqrt{10}}{-2}
=-\frac{22\sqrt{10}}{-2}
=-\frac{11\sqrt{10}}{-1}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{10}}{2*-1}=\frac{0+22\sqrt{10}}{-2}
=\frac{22\sqrt{10}}{-2}
=\frac{11\sqrt{10}}{-1}
$