121=(4x+2)+(3x-7)

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Solution for 121=(4x+2)+(3x-7) equation: 



121=(4x+2)+(3x-7)

We move all terms to the left:

121-((4x+2)+(3x-7))=0



We calculate terms in parentheses: -((4x+2)+(3x-7)), so:

(4x+2)+(3x-7)

We get rid of parentheses

4x+3x+2-7

We add all the numbers together, and all the variables

7x-5

Back to the equation:

-(7x-5)



We get rid of parentheses

-7x+5+121=0

We add all the numbers together, and all the variables

-7x+126=0

We move all terms containing x to the left, all other terms to the right

-7x=-126

x=-126/-7

x=+18

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