121=(6+x)(x)

Solution for 121=(6+x)(x) equation:

121=(6+x)(x)

We move all terms to the left:

121-((6+x)(x))=0

We add all the numbers together, and all the variables

-((x+6)x)+121=0


We calculate terms in parentheses: -((x+6)x), so:

(x+6)x

We multiply parentheses

x^2+6x

Back to the equation:

-(x^2+6x)


We get rid of parentheses

-x^2-6x+121=0

We add all the numbers together, and all the variables

-1x^2-6x+121=0

a = -1; b = -6; c = +121;
Δ = b2-4ac
Δ = -62-4·(-1)·121
Δ = 520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{520}=\sqrt{4*130}=\sqrt{4}*\sqrt{130}=2\sqrt{130}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{130}}{2*-1}=\frac{6-2\sqrt{130}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{130}}{2*-1}=\frac{6+2\sqrt{130}}{-2}
$