121=f2

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Solution for 121=f2 equation:



121=f2
We move all terms to the left:
121-(f2)=0
We add all the numbers together, and all the variables
-1f^2+121=0
a = -1; b = 0; c = +121;
Δ = b2-4ac
Δ = 02-4·(-1)·121
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22}{2*-1}=\frac{-22}{-2} =+11 $
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22}{2*-1}=\frac{22}{-2} =-11 $

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