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121=n2
We move all terms to the left:
121-(n2)=0
We add all the numbers together, and all the variables
-1n^2+121=0
a = -1; b = 0; c = +121;
Δ = b2-4ac
Δ = 02-4·(-1)·121
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22}{2*-1}=\frac{-22}{-2} =+11 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22}{2*-1}=\frac{22}{-2} =-11 $
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