121n-3=7(n-4)+5n

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Solution for 121n-3=7(n-4)+5n equation: 



121n-3=7(n-4)+5n

We move all terms to the left:

121n-3-(7(n-4)+5n)=0



We calculate terms in parentheses: -(7(n-4)+5n), so:

7(n-4)+5n

We add all the numbers together, and all the variables

5n+7(n-4)

We multiply parentheses

5n+7n-28

We add all the numbers together, and all the variables

12n-28

Back to the equation:

-(12n-28)



We get rid of parentheses

121n-12n+28-3=0

We add all the numbers together, and all the variables

109n+25=0

We move all terms containing n to the left, all other terms to the right

109n=-25

n=-25/109

n=-25/109

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