121n2=36

Solution for 121n2=36 equation:

121n^2=36

We move all terms to the left:

121n^2-(36)=0

a = 121; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·121·(-36)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-132}{2*121}=\frac{-132}{242}
=-6/11
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+132}{2*121}=\frac{132}{242}
=6/11
$