122/3x+41/6=40+51/2

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Solution for 122/3x+41/6=40+51/2 equation: 



122/3x+41/6=40+51/2

We move all terms to the left:

122/3x+41/6-(40+51/2)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

122/3x+41/6-(51/2+40)=0

We get rid of parentheses

122/3x-40+41/6-51/2=0

We calculate fractions

There is no solution for this equation

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