122=1/2(96+x)

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Solution for 122=1/2(96+x) equation:



122=1/2(96+x)
We move all terms to the left:
122-(1/2(96+x))=0
Domain of the equation: 2(96+x))!=0
x∈R
We add all the numbers together, and all the variables
-(1/2(x+96))+122=0
We multiply all the terms by the denominator
-(1+122*2(x+96))=0
We calculate terms in parentheses: -(1+122*2(x+96)), so:
1+122*2(x+96)
determiningTheFunctionDomain 122*2(x+96)+1
Wy multiply elements
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Back to the equation:
-(244x(x+1)
We calculate terms in parentheses: -(244x(x+1), so:
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We calculate terms in parentheses: -(244x(x+1), so:
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We calculate terms in parentheses: -(244x(x+1), so:
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We calculate terms in parentheses: -(244x(x+1), so:
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We calculate terms in parentheses: -(244x(x+1), so:
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We calculate terms in parentheses: -(244x(x+1), so:
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We calculate terms in parentheses: -(244x(x+1), so:
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We calculate terms in parentheses: -(244x(x+1), so:
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We calculate terms in parentheses: -(244x(x+1), so:
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We calculate terms in parentheses: -(244x(x+1), so:
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We calculate terms in parentheses: -(244x(x+1), so:
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We calculate terms in parentheses: -(244x(x+1), so:
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We calculate terms in parentheses: -(244x(x+1), so:
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