122=16+4x

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Solution for 122=16+4x equation: 



122=16+4x

We move all terms to the left:

122-(16+4x)=0

We add all the numbers together, and all the variables

-(4x+16)+122=0

We get rid of parentheses

-4x-16+122=0

We add all the numbers together, and all the variables

-4x+106=0

We move all terms containing x to the left, all other terms to the right

-4x=-106

x=-106/-4

x=26+1/2

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