122=2x+6(2x-3)

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Solution for 122=2x+6(2x-3) equation: 



122=2x+6(2x-3)

We move all terms to the left:

122-(2x+6(2x-3))=0



We calculate terms in parentheses: -(2x+6(2x-3)), so:

2x+6(2x-3)

We multiply parentheses

2x+12x-18

We add all the numbers together, and all the variables

14x-18

Back to the equation:

-(14x-18)



We get rid of parentheses

-14x+18+122=0

We add all the numbers together, and all the variables

-14x+140=0

We move all terms containing x to the left, all other terms to the right

-14x=-140

x=-140/-14

x=+10

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