122=4(4x+4)

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Solution for 122=4(4x+4) equation: 



122=4(4x+4)

We move all terms to the left:

122-(4(4x+4))=0



We calculate terms in parentheses: -(4(4x+4)), so:

4(4x+4)

We multiply parentheses

16x+16

Back to the equation:

-(16x+16)



We get rid of parentheses

-16x-16+122=0

We add all the numbers together, and all the variables

-16x+106=0

We move all terms containing x to the left, all other terms to the right

-16x=-106

x=-106/-16

x=6+5/8

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