122=7(z-8)-5(6+z)

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Solution for 122=7(z-8)-5(6+z) equation: 



122=7(z-8)-5(6+z)

We move all terms to the left:

122-(7(z-8)-5(6+z))=0

We add all the numbers together, and all the variables

-(7(z-8)-5(z+6))+122=0



We calculate terms in parentheses: -(7(z-8)-5(z+6)), so:

7(z-8)-5(z+6)

We multiply parentheses

7z-5z-56-30

We add all the numbers together, and all the variables

2z-86

Back to the equation:

-(2z-86)



We get rid of parentheses

-2z+86+122=0

We add all the numbers together, and all the variables

-2z+208=0

We move all terms containing z to the left, all other terms to the right

-2z=-208

z=-208/-2

z=+104

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