122=9x*x

Solution for 122=9x*x equation:

122=9x*x

We move all terms to the left:

122-(9x*x)=0

We add all the numbers together, and all the variables

-(+9x*x)+122=0

We get rid of parentheses

-9x*x+122=0

Wy multiply elements

-9x^2+122=0

a = -9; b = 0; c = +122;
Δ = b2-4ac
Δ = 02-4·(-9)·122
Δ = 4392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4392}=\sqrt{36*122}=\sqrt{36}*\sqrt{122}=6\sqrt{122}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{122}}{2*-9}=\frac{0-6\sqrt{122}}{-18}
=-\frac{6\sqrt{122}}{-18}
=-\frac{\sqrt{122}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{122}}{2*-9}=\frac{0+6\sqrt{122}}{-18}
=\frac{6\sqrt{122}}{-18}
=\frac{\sqrt{122}}{-3}
$