123=2x+(x+42)

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Solution for 123=2x+(x+42) equation: 



123=2x+(x+42)

We move all terms to the left:

123-(2x+(x+42))=0



We calculate terms in parentheses: -(2x+(x+42)), so:

2x+(x+42)

We get rid of parentheses

2x+x+42

We add all the numbers together, and all the variables

3x+42

Back to the equation:

-(3x+42)



We get rid of parentheses

-3x-42+123=0

We add all the numbers together, and all the variables

-3x+81=0

We move all terms containing x to the left, all other terms to the right

-3x=-81

x=-81/-3

x=+27

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