124=-16t2+124t+5

Solution for 124=-16t2+124t+5 equation:

124=-16t^2+124t+5

We move all terms to the left:

124-(-16t^2+124t+5)=0

We get rid of parentheses

16t^2-124t-5+124=0

We add all the numbers together, and all the variables

16t^2-124t+119=0

a = 16; b = -124; c = +119;
Δ = b2-4ac
Δ = -1242-4·16·119
Δ = 7760
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7760}=\sqrt{16*485}=\sqrt{16}*\sqrt{485}=4\sqrt{485}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-124)-4\sqrt{485}}{2*16}=\frac{124-4\sqrt{485}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-124)+4\sqrt{485}}{2*16}=\frac{124+4\sqrt{485}}{32}
$