124=4(4a+3)

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Solution for 124=4(4a+3) equation: 



124=4(4a+3)

We move all terms to the left:

124-(4(4a+3))=0



We calculate terms in parentheses: -(4(4a+3)), so:

4(4a+3)

We multiply parentheses

16a+12

Back to the equation:

-(16a+12)



We get rid of parentheses

-16a-12+124=0

We add all the numbers together, and all the variables

-16a+112=0

We move all terms containing a to the left, all other terms to the right

-16a=-112

a=-112/-16

a=+7

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