124=4(6b+3)+4b

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Solution for 124=4(6b+3)+4b equation: 



124=4(6b+3)+4b

We move all terms to the left:

124-(4(6b+3)+4b)=0



We calculate terms in parentheses: -(4(6b+3)+4b), so:

4(6b+3)+4b

We add all the numbers together, and all the variables

4b+4(6b+3)

We multiply parentheses

4b+24b+12

We add all the numbers together, and all the variables

28b+12

Back to the equation:

-(28b+12)



We get rid of parentheses

-28b-12+124=0

We add all the numbers together, and all the variables

-28b+112=0

We move all terms containing b to the left, all other terms to the right

-28b=-112

b=-112/-28

b=+4

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