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124=x2+2x
We move all terms to the left:
124-(x2+2x)=0
We add all the numbers together, and all the variables
-(+x^2+2x)+124=0
We get rid of parentheses
-x^2-2x+124=0
We add all the numbers together, and all the variables
-1x^2-2x+124=0
a = -1; b = -2; c = +124;
Δ = b2-4ac
Δ = -22-4·(-1)·124
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10\sqrt{5}}{2*-1}=\frac{2-10\sqrt{5}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10\sqrt{5}}{2*-1}=\frac{2+10\sqrt{5}}{-2} $
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