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125=(1/2)(2)(x)
We move all terms to the left:
125-((1/2)(2)(x))=0
Domain of the equation: 2)2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-((+1/2)2x)+125=0
We multiply all the terms by the denominator
-((+1+125*2)2x)=0
We calculate terms in parentheses: -((+1+125*2)2x), so:x=0/-2512
(+1+125*2)2x
We add all the numbers together, and all the variables
2512x
Back to the equation:
-(2512x)
x=0
Równanie nie ma rozwiązania
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